12PHYS - Electricity
Finn Le Sueur
2024
\[ \begin{aligned} & n = \frac{0.03}{1.6\times10^{-19}} \newline & n = 1.875\times10^{17} \end{aligned} \]
\[ \begin{aligned} & I = \frac{q}{t} \newline & It = q \newline & q = 0.08 \times 1 = 0.08C \newline & n = \frac{0.08}{1.6\times^{-19}} = 5\times10^{17} \end{aligned} \]
\[ \begin{aligned} & P = IV, V = IR\newline & P = I^{2}R \newline & P = 0.08^{2} \times 2000 = 12.8W (Js^{-1}) \end{aligned} \]
Think, pair and share!
The force (\(F\)) that the charge experiences as it moves through the field depends on three things:
\[ \begin{aligned} F = Bqv \end{aligned} \]
Let’s summarise:
Electric Field: A region in which a charged object experiences a force \(F=Eq\)
Magnetic Field: A region in which a moving charged object experiences a force \(F=Bqv\)
A narrow beam of protons (\(1.6\times10^{-19}C\)) moving at a speed of \(2.0\times10^{-6}ms^{-1}\), enters a uniform magnetic field of strength \(0.20T\).
Calculate the magnetic force applied on each proton.
\[ \begin{aligned} & F = Bqv \newline & F = 0.2 \times 1.6\times10^{-19} \times 2.0\times10^{-6} \newline & F = 6.4 \times 10^{-26}N \end{aligned} \]
Thumb in the direction of positive charge velocity, finger-tips indicate the \(B\) field strength, and the palm shows the direction of force on the positive charge.
Thumb in the direction of NEGATIVE charge velocity, finger-tips indicate the \(B\) field direction, and the back of the hand shows the direction of force on the NEGATIVE charge.
By default we use the +ve charge rule because we tend to think about conventional current (the flow of +ve charge).
For each of these four situations, apply the RH rule and figure out what direction the current feels a force. Fingers go in direction of field and thumb in direction of current.
A cross means current going into the page down a wire; a dot means current coming out of the page.
A charged object (\(q=1.6\times10^{-19}C\)) moves to the left across a magnetic field (going bottom to top of the page) with a speed of \(4.0\times10^{3}ms^{-1}\). The magnetic field strength is \(12T\).
Textbook page 235 Q1-2