Mahi Tuatahi 🔗
- If an object has a charge of $0.03C$, how many electrons has it lost?
- There is $80mA$ of current flowing through a $2k\Omega$ resistor. How many electrons are going through the resistor in one second?
- What is the power output of the resistor?
Whakatika Tahi 🔗
$$ \begin{aligned} & n = \frac{0.03}{1.6\times10^{-19}} \newline & n = 1.875\times10^{17} \end{aligned} $$
Whakatika Rua 🔗
$$ \begin{aligned} & I = \frac{q}{t} \newline & It = q \newline & q = 0.08 \times 1 = 0.08C \newline & n = \frac{0.08}{1.6\times^{-19}} = 5\times10^{17} \end{aligned} $$
Whakatika Toru 🔗
$$ \begin{aligned} & P = IV, V = IR\newline & P = I^{2}R \newline & P = 0.08^{2} \times 2000 = 12.8W (Js^{-1}) \end{aligned} $$
Pātai: What is an electric field? 🔗
Think, pair and share!
- A region in which a charged object experiences a force
What is a magnetic field? 🔗
- A region in which a moving charged object experiences a force
Magnetic Force: Particles 🔗
The force ($F$) that the charge experiences as it moves through the field depends on three things:
- Magnetic field strength ($B$, measured in Tesla ($T$))
- Charge of the object ($q$, measured in Coulombs ($C$))
- Velocity of the object ($v$, measured in $ms^{-1}$)
$$ \begin{aligned} F = Bqv \end{aligned} $$
Let’s summarise:
Electric Field: A region in which a charged object experiences a force $F=Eq$
Magnetic Field: A region in which a moving charged object experiences a force $F=Bqv$
Why Do Magnetic Fields Form? 🔗
- A model that will help us understand is as follows:
- The valence electrons of each atom have some small magnetic component to them
- When all of the atoms are aligned, their magnetic fields all add up to a much stronger/larger field
Ferromagnets and Paramagnets 🔗
- Ferromagnet: A material where the atoms are all aligned to create a permanent magnetic field
- E.g. Iron, nickel, cobalt, and their alloys
- Paramagnets: A material with disorderly atoms, but that can become aligned when exposed to a strong external magnetic field.
- E.g. Platinum, aluminium, oxygen, copper
Pātai 🔗
A narrow beam of protons ($1.6\times10^{-19}C$) moving at a speed of $2.0\times10^{-6}ms^{-1}$, enters a uniform magnetic field of strength $0.20T$.
Calculate the magnetic force applied on each proton.
Whakatika 🔗
$$ \begin{aligned} & F = Bqv \newline & F = 0.2 \times 1.6\times10^{-19} \times 2.0\times10^{-6} \newline & F = 6.4 \times 10^{-26}N \end{aligned} $$
Right-Hand Slap Rule (+ve Charges) 🔗
Thumb in the direction of positive charge velocity, finger-tips indicate the $B$ field strength, and the palm shows the direction of force on the positive charge.
Back-Hand Slap Rule (-ve Charges) 🔗
Thumb in the direction of NEGATIVE charge velocity, finger-tips indicate the $B$ field direction, and the back of the hand shows the direction of force on the NEGATIVE charge.
By default we use the +ve charge rule because we tend to think about conventional current (the flow of +ve charge).
Pātai 🔗
For each of these four situations, apply the RH rule and figure out what direction the current feels a force. Fingers go in direction of field and thumb in direction of current.
A cross means current going into the page down a wire; a dot means current coming out of the page.
Whakatika 🔗
- Force out of the page
- Force into the page
- Force down
- Force up
Pātai 🔗
A charged object ($q=1.6\times10^{-19}C$) moves to the left across a magnetic field (going bottom to top of the page) with a speed of $4.0\times10^{3}ms^{-1}$. The magnetic field strength is $12T$.
- Draw a diagram and illustrate the magnetic field lines
- Calculate the force applied to the charged object
- Describe/draw the direction of the force applied
Cathode Ray Tube & Magnets 🔗
- Collect a Cathode Ray Tube and Magnets sheet
- Come up the front where you can observe the CRT monitor.
- Use our discussion and information at the top to answer Task 1-2.
Whakawai 🔗
Textbook page 235 Q1-2