Pātai/Question ^🔗

• Recall $F=Bqv$
• What happens if we take a wire and we move it through a magnetic field?

Whakatika ^🔗

1. The charged particles (electrons) are now moving through an electric field, and therefore feel a force!
2. The force exerted on the moving electrons by the magnetic field will cause them to accelerate and therefore to move
3. If the circuit is complete: a. Moving electrons is known as a induced current! b. Moving electrons will cause an unequal distribution (difference in potential), known as induced voltage.

Inductors Summary ^🔗

Moving charges through a magnetic field will cause them to feel a force (due to the magnetic field). Thus creating an induced voltage.

In a complete circuit, this is seen as a induced current.

Induced Voltage ^🔗

Exists in a conductor moving through a magnetic field in a perpendicular direction.

$$ \begin{aligned} & V=BvL \end{aligned} $$

• $V$ is the induced voltage (V, Volts)
• $B$ is the magnetic field strength (T, Tesla)
• $v$ is the velocity of the condutor ($ms^{-1}$)
• $L$ is the length of the condutor in the field ($m$)

Pātai ^🔗

A metal rod is moved in a magnetic field. The rod is $24cm$ long and moves at $8ms^{-1}$ through a magnetic field with strength $0.7T$.

1. Calculate the induced voltage
2. Calculate the induced current and indicate direction

Whakatika ^🔗

$$ \begin{aligned} & V = BvL \newline & V = 0.7 \times 8 \times 0.24 \newline & V = 1.344V \end{aligned} $$

$$ \begin{aligned} & V = IR \newline & I = \frac{V}{R} \newline & I = \frac{1.344}{10} = 0.1344A \end{aligned} $$