Mahi Tuatahi 🔗
- Yssy travels 30km south and then 20km west. Draw a vector diagram to show her total displacement (resultant).
- Max and Lena are pushing a box. Max is pushing it with force 500N to the right, and Lena is pushing it with force 400N up. Draw a vector diagram to show the net (resultant) force.
- Phoebe is flying at $7ms^{-1}$ east. Phoebe changes direction so she flying at $7ms^{-1}$ south. Draw a vector diagram and calclate her change in velocity.
Te Whāinga Ako 🔗
- Be able to describe the motion of an object undergoing projectile motion.
Write the date and te whāinga ako in your book
Whakamātau/Experiment 🔗
- How many seconds was the student in the air for?
- What is the acceleration due to gravity?
- What was their velocity at the top of their flight?
- How far up did Hancock throw them?
Projectile Motion 🔗
Parabolic motion due to gravity. Friction forces are ignored. Gravity is the only force acting. Motion up and motion down are symmetrical.
Describing Velocity 🔗
We need to be able to describe the velocity and acceleration of an object in projectile motion.
Forces on Projectiles 🔗
- We assume that friction force is negligible (we ignore it).
- Therefore, the only force acting upon the ball while in the air is the weight force.
- Weight force acts in the vertical direction only ($a_{y} = g = 9.8ms^{-2}, v_{y} \ne const.$)
- No forces act in the horizontal ($a_{x} = 0, v_{x}=const.$)
Acceleration Due to Gravity 🔗
Has the same magnitude at all points ($9.8ms^{-2}$) and always points downwards.
Projectile Motion: In Summary 🔗
- An object that moves through the air without its own power source;
- the only force acting upon it is the weight force;
- it is always experiencing downward acceleration of $9.8ms^{-2}$;
- motion up/down is symmetrical.
- The path is follows is in the shape of a parabola.
Half-Projectile Motion: Pātai Tahi 🔗
- How long does it take for the ball to reach its highest point?
- How high does the ball rise?
$$ \begin{aligned} & \textbf{1. Knowns} \cr & \textbf{2. Unknowns} \cr & \textbf{3. Formula} \cr & \textbf{4. Substitute} \cr & \textbf{5. Solve} \end{aligned} $$
Pātai Rua 🔗
- What is the initial velocity of the ball?
- If kicked towards some rugby posts, at its highest point, will it go over the crossbar (3m)?
$$ \begin{aligned} & \textbf{1. Knowns} \cr & \textbf{2. Unknowns} \cr & \textbf{3. Formula} \cr & \textbf{4. Substitute} \cr & \textbf{5. Solve} \cr \end{aligned} $$
Pātai Toru 🔗
- What is his initial velocity?
- What is his acceleration?
- What is his final velocity (as he hits the water)?
- How high is the cliff?
$$ \begin{aligned} & \textbf{1. Knowns} \cr & \textbf{2. Unknowns} \cr & \textbf{3. Formula} \cr & \textbf{4. Substitute} \cr & \textbf{5. Solve} \cr \end{aligned} $$
Whakawai/Practise 🔗
- Textbook Page 137: Activity 12A Q1, Q3
Full Projectile Motion 🔗
- Weight force is the only force acting.
- The cannonball accelerates in the y direction ($a_{y} = g = 9.8ms^{-2}$).
- No forces are acting in the horizontal direction, so velocity is constant ($a_{x} = 0$).
Example / Tauria 🔗
- First, using trig, calculate the initial horizontal ($v_{x}$) and vertical ($v_{y}$) velocities
- Second, using vertical values, calculate the javelin’s time of flight
- Thirdly, using horizontal values, calculate the distance (range) of the javelin
Pātai: Hammer Throw 🔗
- Separate the x and y values that you know.
- Calculate the x and y initial velocities (use a diagram).
- Calculate how long does it take for the projectile to reach the top of its path?
- What is the total time of flight?
- How far can it travel horizontally in that time?
Whakawai/Practise 🔗
- Worksheet #6 Projectiles
Three Types of Projectile Motion 🔗
You need to be able to solve all three types for the exam! We have covered Half and full parabolas so far, now we will do partial parabolas!.
Tauria / Example: Tossing a Ball 🔗
Ben kicks a ball to Elias who is standing $12m$ away. Elias is $180cm$ tall, and the ball has an initial velocity of $7ms^{-1}$ at an angle of $37^{\circ}$ to the horizontal. Does the ball travel over Elias’ head, hit them, or fall short?
- Calculate the x and y components of the initial velocity
- Think Horizontal: Calculate the time taking for the ball to reach Elias
- Think Vertical: What is the height (d) at time t (from above)?
- Turn your numerical answer into a sentence explaining what you found.
Whakatika 🔗
- Calculate the x and y components of the initial velocity
$$ \begin{aligned} v_{x} &= vcos(\theta) = 7cos(37) = 5.59ms^{-1} \cr v_{y} &= vsin(\theta) = 7sin(37) = 4.21ms^{-1} \end{aligned} $$
- Think Horizontal: Calculate the time taking for the ball to reach Elias
$$ \begin{aligned} &\text{K: } v_{xi} = 5.59ms^{-1}, a_{x} = 0ms^{-1}, d_{x} = 12m \cr &\text{U: } t = ? \cr &\text{F: } d = v_{i}t + \frac{1}{2}at^{2} \cr &\text{S: } 12 = 5.59 \times t + \frac{1}{1} \times 0 \times t^{2} \cr &\text{S: } \frac{12}{5.59} = t = 2.15s \end{aligned} $$
- Think Vertical: What is the height (d) at time t (from above)?
$$ \begin{aligned} &\text{K: } v_{yi} = 4.21ms^{-1}, a = 9.8ms^{-2}, t = 2.15s \cr &\text{U: } d = ? \cr &\text{F: } d = v_{i}t + \frac{1}{2}at^{2} \cr &\text{S: } d = (4.21 \times 2.15) + (0.5 \times -9.8 \times 2.15^{2}) \cr &\text{S: } d = -13.60m \end{aligned} $$
A height of $-13.60m$ indicates that it is lower than where it begin. This means that it fell short of Elias and hit the ground.
Practice Your Parabolas! 🔗
You need to be able to solve all three types for the exam! We have covered Half and full parabolas so far, now we will do partial parabolas!.